输入一个链表,输出该链表中倒数第k个结点。
/*
public class ListNode {
int val;
ListNode next = null;
ListNode(int val) {
this.val = val;
}
}*/
public class Solution {
public ListNode FindKthToTail(ListNode head,int k) {
ListNode fast = head;
ListNode slow = head;
int a = k;
int count = 0;
while(fast!=null){
fast = fast.next;
count ++;
if(k<1){
slow = slow.next;
}
k--;
}
if(count < a){
return null;
}
return slow;
}
}
快指针走一步,慢指针先不走,等到快指针走了K步之后,慢指针开始走,如果所有的步数之和大于K,说明慢指针