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Algorithm

199. Binary Tree Right Side View (二叉树右视图)

Description

Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.

Example:

Input: [1,2,3,null,5,null,4]
Output: [1, 3, 4]
Explanation:

   1            <---
 /   \
2     3         <---
 \     \
  5     4       <---

Solution

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<Integer> rightSideView(TreeNode root) {
        List<Integer> list = new ArrayList<>();
        Queue<TreeNode> queue = new LinkedList<>();
        if(root == null){
          return list;
        }
        queue.add(root);
        while(!queue.isEmpty()){
           int size = queue.size();
           for(int i=0; i<size; i++){
              TreeNode node = queue.poll();
              if(node.left!=null){
                queue.add(node.left);
              }
              if(node.right!=null){
                queue.add(node.right);
              }
              if(i == size-1){
                list.add(node.val);
              }
           }
        }
        return list;
    }
}

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