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Algorithm

209. Minimum Size Subarray Sum

Description

Given an array of positive integers nums and a positive integer target, return the minimal length of a contiguous subarray [numsl, numsl+1, ..., numsr-1, numsr] of which the sum is greater than or equal to target. If there is no such subarray, return 0 instead.

Example 1:

Input: target = 7, nums = [2,3,1,2,4,3]
Output: 2
Explanation: The subarray [4,3] has the minimal length under the problem constraint.

Example 2:

Input: target = 4, nums = [1,4,4]
Output: 1

Example 3:

Input: target = 11, nums = [1,1,1,1,1,1,1,1]
Output: 0

Constraints:

  • 1 <= target <= 109

  • 1 <= nums.length <= 105

  • 1 <= nums[i] <= 105

  • Follow up: If you have figured out the O(n) solution, try coding another solution of which the time complexity is O(n log(n)).

Solution

class Solution {
   public int minSubArrayLen(int s, int[] nums) {
       int start = 0, end = 0;
       int min = Integer.MAX_VALUE, sum = 0;
       while(end<=nums.length){
           if(sum >= s){
              min = Math.min(min, end - start);
              sum -= nums[start++];
           }else{
              if(end==nums.length){
                  end++;
              }else{
                  sum += nums[end++];
              }
           }
       }
       return (min == Integer.MAX_VALUE) ? 0:min;
   }
}

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