Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
A subarray is a contiguous part of an array.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Example 2:
Input: nums = [1]
Output: 1
Example 3:
Input: nums = [5,4,-1,7,8]
Output: 23
Constraints:
- 1 <= nums.length <= 105
- -104 <= nums[i] <= 104
Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
class Solution {
public int maxSubArray(int[] nums) {
if(nums==null||nums.length==0){
return 0;
}
int sum = nums[0];
int max = nums[0];
for(int i=1;i<nums.length;i++){
if(sum + nums[i] > nums[i]){
sum += nums[i];
}else{
sum = nums[i];
}
max = Math.max(sum, max);
}
return max;
}
}