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Algorithm

204. Count Primes

Description

Given an integer n, return the number of prime numbers that are strictly less than n.

Example 1:

Input: n = 10
Output: 4
Explanation: There are 4 prime numbers less than 10, they are 2, 3, 5, 7.

Example 2:

Input: n = 0
Output: 0

Example 3:

Input: n = 1
Output: 0

Constraints:

  • 0 <= n <= 5 * 106

Solution

class Solution {
    public int countPrimes(int n) {
        boolean[] notPrime = new boolean[n];
        int count = 0;
        for (int i = 2; i < n; i++) {
            if (notPrime[i] == false) {
                count++;
                for (int j = 2; i*j < n; j++) {
                    notPrime[i*j] = true;
                }
            }
        }

        return count;
    }
}
class Solution {
    public int countPrimes(int n) {
        boolean[] isPrime = new boolean[n];
        Arrays.fill(isPrime, true);
        for(int i=2;i*i<n;i++){
            if(isPrime[i]){
                for(int j=i*i;j<n;j+=i){
                    isPrime[j] = false;
                }
            }
        }

        int count = 0;
        for(int i=2;i<n;i++){
            if(isPrime[i]){
                count++;
            }
        }

        return count;
    }
}

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